Write an equation in standard form that has a slip of 6 and passes through (-1,3)

Answer:6x - y = -9Step-by-step explanation:The point-slope form of an equation of a line:[tex]y-y_1=m(x-x_1)[/tex]m - slope(x₁, y₁) - point on a lineWe have[tex]m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3[/tex]Substitute:[tex]y-3=6(x-(-1))[/tex][tex]y-3=6(x+1)[/tex]Convert to the standard form Ax + By = C:[tex]y-3=6(x+1)[/tex]         use the distributive property a(b + c) = ab + ac[tex]y-3=6x+6[/tex]          add 3 to both sides[tex]y=6x+9[/tex]         subtract 6x from both sides[tex]-6x+y=9[/tex]          change all signs[tex]6x-y=-9[/tex]